If a rectangle has perimeter 40 and length 12, what is its width?

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Multiple Choice

If a rectangle has perimeter 40 and length 12, what is its width?

Explanation:
Rectangle perimeter equals twice the sum of its length and width, so P = 2(L + W). With P = 40 and L = 12, 40 = 2(12 + W). Divide by 2 to get 20 = 12 + W, so W = 8. This width indeed gives a perimeter of 2(12 + 8) = 40. The other options would produce larger perimeters: 10 yields 44, 12 yields 48, and 14 yields 52.

Rectangle perimeter equals twice the sum of its length and width, so P = 2(L + W). With P = 40 and L = 12, 40 = 2(12 + W). Divide by 2 to get 20 = 12 + W, so W = 8. This width indeed gives a perimeter of 2(12 + 8) = 40. The other options would produce larger perimeters: 10 yields 44, 12 yields 48, and 14 yields 52.

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